LeetCode 954. Array of Doubled Pairs

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
class Solution {
public:
    bool canReorderDoubled([......]<p class="read-more"><a href="https://www.gerrytang.top/?p=310">Read more</a></p>

LeetCode 704. Binary Search

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
class Solution {
public:
    int search(vector& nums[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=304">Read more</a></p>

LeetCode 816. Ambiguous Coordinates

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
class Solution {
private:
    inline vector sub(stri[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=302">Read more</a></p>

LeetCode 894. All Possible Full Binary Trees

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
/**
 * Definition for a binary tree node.
 * struct[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=300">Read more</a></p>

LeetCode 797. All Paths From Source to Target

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
class Solution {
public:
    vector allPathsSourceTa[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=298">Read more</a></p>

LeetCode 432. All O`one Data Structure

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();

class Node{
public:
    string key;
    int cou[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=296">Read more</a></p>

LeetCode 863. All Nodes Distance K in Binary Tree

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static auto x = []()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return 0;
}();
/**
 * Definition for a binary tree node.
 * struct[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=294">Read more</a></p>

LeetCode 306. Additive Number

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long get(char* num,int len){
    long ret=0;
    for(int i=0;i=0;i--){
        if(num[i]-'0'==t%10){
            t/=10;
        }
        else[......]<p class="read-more"><a href="https://www.gerrytang.top/?p=292">Read more</a></p>