LeetCode 1528. Shuffle String

Given a string s and an integer array indices of the same length.

The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string.

Return the shuffled string.

Example 1:

Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:

Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Example 3:

Input: s = "aiohn", indices = [3,1,4,2,0]
Output: "nihao"
Example 4:

Input: s = "aaiougrt", indices = [4,0,2,6,7,3,1,5]
Output: "arigatou"
Example 5:

Input: s = "art", indices = [1,0,2]
Output: "rat"

Constraints:

s.length == indices.length == n
1 <= n <= 100
s contains only lower-case English letters.
0 <= indices[i] < n
All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n – 1).

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char * restoreString(char * s, int* indices, int indicesSize){
    char* ret=(char*)malloc(sizeof(char)*(indicesSize+1));
    for(int i=0;i<indicesSize;++i){
        ret[indices[i]]=s[i];
    }
    ret[indicesSize]='\0';
    return ret;
}


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