Given a m * n matrix grid which is sorted in non-increasing order both row-wise and column-wise.

Return the number of negative numbers in grid.

Example 1:

Input: grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]

Output: 8

Explanation: There are 8 negatives number in the matrix.

Example 2:

Input: grid = [[3,2],[1,0]]

Output: 0

Example 3:

Input: grid = [[1,-1],[-1,-1]]

Output: 3

Example 4:

Input: grid = [[-1]]

Output: 1

Constraints:

m == grid.length

n == grid[i].length

1 <= m, n <= 100

-100 <= grid[i][j] <= 100

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | int countNegatives(int** grid, int gridSize, int* gridColSize){ int cnt=0; int firstIndex = *gridColSize; for(int i=0;i<gridSize;++i){ while(firstIndex>0 && grid[i][firstIndex-1]<0){ --firstIndex; } if(firstIndex==0){ cnt += *gridColSize * (gridSize-i); break; } else{ cnt += *gridColSize - firstIndex; } } return cnt; } |

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